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4 years ago

8+3b+-13 WHO WANTS 99 POINTS XD

Mathematics

2 answers:

BARSIC [14]4 years ago

5 0

Answer:

$\Huge\boxed{3b-5}$

Step-by-step explanation:

$\Large\boxed{\mathsf{SUBJECT: MATH}}}$

Isolate b on one side of the equation.

First, subtract.

8-13=-5

3b-5

$\Large\boxed{\mathsf{\Rightarrow 3b-5}}$

So, the correct answer is 3b-5.

LenKa [72]4 years ago

4 0

Answer:

3b - 5

Step-by-step explanation:

8 + 3b + - 13

Combine like terms

8 +-13 = 8 - 13

8 - 13 = -5

Write it out together

3b - 5

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4 years ago

A. What is the probability that this couple spends 45 dollars or more?

guapka [62]

Using the probability table, it is found that:

a) There is a 0.25 = 25% probability that this couple spends 45 dollars or more.

b) The expected amount the couple actually has to pay is $36.85.

Item a:

To find the probabilities involving the total cost, we have to add the variables X and Y from the table, then:

$P(X = 30) = P(X = 15|Y = 15) = 0.2$

$P(X = 35) = P(X = 15|Y = 20) + P(X = 20|Y = 15) = 0.15 + 0.15 = 0.3$

$P(X = 40) = P(X = 15|Y = 25) + P(X = 20|Y = 20) + P(X = 25|Y = 15) = 0.05 + 0.15 + 0.05 = 0.25$

$P(X = 45) = P(X = 20|Y = 25) + P(X = 25|Y = 20) = 0.1 + 0.1 = 0.2$

$P(X = 50) = P(X = 25|Y = 25) = 0.05$

The probability involving values of 45 or more is:

$P(X \geq 45) = P(X = 45) + P(X = 50) = 0.2 + 0.05 = 0.25$

0.25 = 25% probability that this couple spends 45 dollars or more.

Item b:

For a discrete distribution, the expected value is the sum of each outcome multiplied by it's respective probability, hence, involving the 10% discount for prices above $45:

$E(X) = 0.2(30) + 0.3(35) + 0.25(40) + 0.9[0.2(45) + 0.05(50)] = 36.85$

The expected amount the couple actually has to pay is $36.85

A similar problem is given at brainly.com/question/25782059

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2 years ago

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3 years ago

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3 years ago

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4 years ago