Answer:
45
Step-by-step explanation:
AEF is a similar triangle to ABC. that means it has the same angles, and the sides (and all other lines in the triangle) are scaled from the ABC length to the AEF length by the same factor f.
now, what is f ?
we know this from the relation of AC to FA.
FA = 12 mm
AC = 12 + 28 = 40 mm
so, going from AC to FA we multiply AC by f so that
AC × f = FA
40 × f = 12
f = 12/40 = 3/10
all other sides, heights, ... if ABC translate to their smaller counterparts in AEF by that multiplication with f (= 3/10).
the area of a triangle is
baseline × height / 2
aABC = 500
and because of the similarity we don't need to calculate the side and height in absolute numbers. we can use the relative sizes by referring to the original dimensions and the scaling factor f.
baseline small = baseline large × f
height small = height large × f
we know that
baseline large × height large / 2 = 500
baseline large × height large = 1000
aAEF = baseline small × height small / 2 =
= baseline large × f × height large × f / 2 =
= baseline large × height large × f² / 2 =
= 1000 × f² / 2 = 500 × f² = 500 ×(3/10)² =
= 500 × 9/100 = 5 × 9 = 45 mm²
Use the table of trigonometric ratios /in a picture/.
Answer: m∠A ≈ 70°
Hello!
We use different formulas to calculate the areas of different shape.
RECTANGLE:
To find the area of a rectangle, we must simply multiply its length by its width. The formula for its area is:
A = l × w
SEMICIRCLE:
Since the formula for a circle is pi × r × r, we must use the same formula but divide it in half, because a semicircle is a half circle, which is why its area would also be half of a circle's. The formula for a semicircle's area is:
A = 1/2 pi × r × r
Tip:
Write these formulas down and memorize them so that you don't forget them. You'll have to use these formulas quite often when finding the area of these shapes.
Answer:
1/2
Step-by-step explanation:
Answer:
8 different combinations are possible.
Step-by-step explanation:
Here, we have 2 different combinations for each time.
And the player comes out to bat 3 times.
So, total number of combinations are:
i.e. a total of 8 number of times.
Let a hit is termed as 'H' and an out is termed as 'O'.
Total combinations are:
{HHH, HHO, HOH, HOO, OHH, OHO, OOH, OOO}
Kindly have a look at the tree diagram attached in the answer area.
In starting, there are 2 combinations possible, i.e. 'O' and 'H'.
After 'O' , 2 possible i.e. 'O' and 'H'.
After 'H' , 2 possible i.e. 'O' and 'H'.
and so on....
