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3 years ago

In ΔQRS, q = 1.3 inches, r = 1.6 inches and ∠S=157°. Find the length of s, to the nearest 10th of an inch.

Mathematics

1 answer:

hjlf3 years ago

8 0

Answer:

2.8

Step-by-step explanation:

using cosine rule

$s^{2}$ = $1.3^{2} + 1.6^{2} - 2(1.3)(1.6)cos 157$

s = $\sqrt{8.0793}$ = 2.842 = 2.8

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2 years ago

A smog alert has been called in a certain area of Los Angeles County in which there are 50 industrial rms. An inspector will vis

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Answer:

Part (A) The required PMF is: $P(X=x)=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

Part (B) $B(x;n,p)=\binom{10}{x}(0.3)^x(1-0.3)^{10-x}$

Step-by-step explanation:

Consider the provided information.

There are 50 industrial rms. An inspector will visit 10 randomly selected rms to check for violations of regulations.

Part (A)

15 of the rms are actually violating at least one regulation.

Let X is the number of firms violate at least one regulation from 10 randomly selected rms to check for violations of regulations out of 50 firms of which 15 5 of the rms are actually violating.

Therefore, $X\sim Hypergeom(n=10, M=15\ and\ N=50)$

We need to determine probability mass function.

$P(X=x)=Hyper(x; n=10, M=15, N=50)\\=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

Hence, the required PMF is: $P(X=x)=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

Part (B) If there are 500 rms in the area, of which 150 are in violation, approximate the pmf of part.

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3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

if every 5 days the number quadruples (x4), and we want to know how many acorns fall after 30 days, we can divide 30 by 5 so we only have to calculate for the amount of time the take to quadruple.

30 ÷ 5 = 6

so we only have to quadruple the acorns 6 times.

if we start off with 124 acorns, this is what it will look like:

Day 0: 124 acorns

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Day 10: 496 x 4 = 1984 acorns

Day 15: 1984 x 4 = 7936 acorns

etc... until day 30.

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I hope this was helpful :-)

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3 years ago