Question

The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70 cm cubed of water.Find the percent of the cup that is filled with water after 3 seconds.

Answer 1

Answer:

In 3 seconds the cup is filled with $105\ cm^3$.

Step-by-step explanation:

Given:

2 seconds = $70\ cm^3$ water

We need to find the percent of the cup that is filled with water after 3 seconds.

Solution:

Now Given:

The cup was filled at a constant rate.

First we will find the volume of water filled in the cup after 1 seconds.

2 seconds = $70\ cm^3$ water

1 seconds = Volume of water filled in 1 second.

By Using Unitary method we get;

Volume of water filled in 1 second = $\frac{70}{2}= 35\ cm^3$

Now we will find the volume of water filled in the cup after 3 seconds.

1 second = $35\ cm^3$ of water is filled

3 seconds = volume of water filled in the cup after 3 seconds

Again by using Unitary method we get;

volume of water filled in the cup after 3 seconds = $35 \times 3 = 105\ cm^3$

Hence In 3 seconds the cup is filled with $105\ cm^3$.

To find the percent of the cup filled with water after 3 seconds we would required the dimensions of the cup which is not available in the question.