3 years ago

What is the middle term of the production of (x-4)(x-3)

Mathematics

1 answer:

Zinaida [17]3 years ago

5 0

See picture for solution to your problem.

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Gina is four years younger than twice David's age. Gina is 18. How old is David?

Sati [7]

Answer:

Step-by-step explanation:

Gina is four years younger so

18+4=22

since its twice davids age

22×2=44

6 0

3 years ago

Which expression represents "eight more than one-tenth a"?

spayn [35]

"eight more than one-tenth a" = 8 + 1/10 a or 1/10 a + 8

Answer

D. 1/10 a + 8

4 0

3 years ago

Read 2 more answers

One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fastt

mash [69]

Answer: $864\ m^2,\ 24\ m$

Step-by-step explanation:

Given

Perimeter of the rhombus is $120\ m$

Length of one of the diagonal is $d_1=36\ m$

All the sides of the rhombus are equal

$\Rightarrow 4a=120\\\Rightarrow a=30\ m$

Area of the rhombus with side and one diagonal is

$\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}$

Insert the values

$\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2$

Area with two diagonals length can be given by

$\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m$

Thus, the area of the rhombus is $864\ m^2$ and the length of the other diagonal is $24\ m$

4 0

3 years ago

1345677865432+1234567890 CAN SOMEONE KILL THIS BRAINLY STUFF

Reptile [31]

Answer:

1.3469124e+12

Step-by-step explanation:

sure

7 0

3 years ago

Expand and simplify 5(2p-3)-2(2+3p)

stira [4]

4p-19
You need to distribute the 5 first then the -2
you will get 10p-15-4-6p
then all you need to do is combine like terms to get 4p-19

6 0

3 years ago