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OLEGan [10]
3 years ago
5

What is the diameter of a sphere with a volume of 498 in3, to the nearest tenth of an inch

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0

Answer:

9.8 inches

Step-by-step explanation:

<h3>Formula for volume of the sphere is = 4/3πr³</h3><h3>Form and solve the equation for the radius</h3><h3>So: 4/3πr³= 498in³</h3><h3>πr³= 498in³*3/4 which = to 373.5in³</h3><h3>r³= 373.5in³/π</h3><h3>r=∛(373.5in³/π)</h3><h3>calculate r and times the result by 2 for diameter</h3><h3>it will be 9.834...</h3><h3>nearest tenth of an inch means the accuracy is 1 decimal place because nearest tenth= 1/10 or 0.1</h3><h3>So the final answer is 9.8in</h3>
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 not sure what format you need, since the question was in fraction form, I think you need to answer using a mixed number though.


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Read 2 more answers
A ferry operator takes tourists to an island.
Oksanka [162]

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<h3>What is Differentiation?</h3>

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Here, The operator for a round-trip fare of $20, carries an average of 500 people per day.

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Learn more about Differentiation from:

brainly.com/question/24062595

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