What is the diameter of a sphere with a volume of 498 in3, to the nearest tenth of an inch

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

3 0

Answer:

9.8 inches

Step-by-step explanation:

<h3>Formula for volume of the sphere is = 4/3πr³</h3><h3>Form and solve the equation for the radius</h3><h3>So: 4/3πr³= 498in³</h3><h3>πr³= 498in³*3/4 which = to 373.5in³</h3><h3>r³= 373.5in³/π</h3><h3>r=∛(373.5in³/π)</h3><h3>calculate r and times the result by 2 for diameter</h3><h3>it will be 9.834...</h3><h3>nearest tenth of an inch means the accuracy is 1 decimal place because nearest tenth= 1/10 or 0.1</h3><h3>So the final answer is 9.8in</h3>

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