A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
x=2
Step-by-step explanation:
Since the angles are equal, the side lengths are equal (isosceles triangle)
12 =6x
Divide by 6
12/6 = 6x/6
2= x
Answer:
The area of trapezium is (x+11) cm².
Step-by-step explanation:
Given that the formula of area of trapezium is :
In the formula, a and b represents the length of trapezium and h is the height. So you have to substitute the following expressions into the formula :
U can either look at ur graph...and where the line crosses the x axis is ur x intercept...which is (-3,0)
OR
take ur equation and sub in 0 for y, and solve for x, ur x intercept.
2x - y = -6
2x - 0 = -6
2x = -6
x = -6/2
x = -3.....so ur x intercept is (-3,0)
Answer:
Step-by-step explanation:
