Given:
Polynomial is
.
To find:
The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.
Solution:
The sum of given polynomial and the square of the binomial (x-8) is

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)

On combining like terms, we get


Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is
.
Answer:
x x x c. c c c c d sbsbbdbcbdbcbbxbcbcbbvbbcbvbcbcbcnc
Answer:
that looks tuff my boy good luck
Step-by-step explanation:
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: cos 330 = 
Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

Proof LHS → RHS:
LHS cos 165
Double-Angle: cos (2 · 165) = 2 cos² 165 - 1
⇒ cos 330 = 2 cos² 165 - 1
⇒ 2 cos² 165 = cos 330 + 1
Given: 

Divide by 2: 

Square root: 
Scratchwork: 

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

LHS = RHS 
Cone Volume = PI * radius^2 * height / 3, which can br rewritten as
Cone Volume = base area * height / 3
Cone Volume = 420mm * 60
Cone Volume = 25,200 cubic mm