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USPshnik [31]
3 years ago
10

a banner is made of a square and a semicircle. The square has side lengths of 26 inches. One side of the square is also the diam

eter of the semicircle. What is the total area of the banner? Use 3.14 for n
Mathematics
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

Okay so all you have to do is find the Area of each shape, then add them together.  Starting with the square.  Your formula is A=s4    All you have to do is plug in your number.  A=26(4) Now solve. A=104.   Now we have to find the area of a semicircle.  Your formula is ((3.14)r squared)(.5) To find the radius (r) you divide the diameter by 2, so 26/2=13     Now all you have to do is plug in your numbers.   (3.14)(13 squared)(.5)    (3.14)(169)(.5)   

(530.66)(.5)   Your final answer is:  265.33 inches squared

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If a shirt was on sale for
sashaice [31]

Answer:

$15

Step-by-step explanation:

You take 50% off of $30, which is 15. You can also think of it as 50% is 1/2. So 1/2 of 30 is 15

6 0
3 years ago
Giving away free points lol<br> what’s 9 - 7
Orlov [11]

Answer:

9-7=2

Step-by-step explanation:

You have 9 dogs and take away 7 dogs you will be left with 2 dogs in your home  :)

and thanksssss

4 0
3 years ago
Read 2 more answers
Find the total surface area of this cuboid.
-Dominant- [34]

Step-by-step explanation:

I just learned this in class lol

Find the area of all the sides.

This cubiod has 6 sides.

6 x 5 = 30

6 x 5 = 30

4 x 5 = 20

4 x 5 = 20

6 x 4 = 24

6 x 4 = 24

30 + 30 + 20 + 20 + 24 + 24 = 148

Thefore, the surface area of this cuboid is 148.

Hope this helps! If it did, please mark it as brainliest! It would help a lot! Thanks! :D

8 0
2 years ago
let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)
statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

\sin (\theta)=\frac{3}{5}

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

x^2+3^2=5^2

Solving for x, we have

\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

\tan (y)=\frac{12}{5}

Describes the following triangle

Using the Pythagorean Theorem again, we have

5^2+12^2=h^2

Solving for h, we have

\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}

To calculate the sine and cosine of the sum

\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}

We can use the following identities

\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}

Using those identities in our problem, we're going to have

\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}

4 0
1 year ago
The triangle below has an area of 75 units squared. Find the missing side.
Volgvan

Answer:

x = 15 units

Step-by-step explanation:

Here, base of triangle = x units & height = 19 units

Area( \triangle) =  \frac{1}{2}  \times base  \times height \\  \\ 75 =  \frac{1}{2}  \times x \times 10 \\  \\ 75 = x \times 5 \\  \\ x =  \frac{75}{5}  \\  \\ \huge \purple{ \boxed{ x = 15 \: units}}

5 0
3 years ago
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