All categories

3 years ago

An iceberg weights 450,000 pounds. If it loses 0.2% of its weight in a day, what is its new weight at the end of the day?

Mathematics

1 answer:

Papessa [141]3 years ago

8 0

Answer:

449,100 pounds

Step-by-step explanation:

.2% as a decimal is 0.002. To find .2% of 450,000, you multiply it. The answer is 900 pounds. Because it is losing that amount, you subtract it. 450,000-900= 449,100 pounds

You might be interested in

What is f (x)=2x^2+5 multiplied by g (x)=2x<br><br>A) 7x+2x<br>B) 4x+10x<br>C)4x^2+10x<br>D)4x^3+10x

Afina-wow [57]

I hope this helps you

5 0

3 years ago

Please help me, I know it’s not the first one but I think it’s the last one. Can somebody please confirm or deny?

GaryK [48]

Answer:

B. 2.2π m² : 3.2π m²

Step-by-step explanation:

Given:

Slant height (l) = 2.2 m

Diameter (d) = 2 m

Radius (r) = ½(2) = 1 m

Required:

Lateral area and surface area

Solution:

✔️Formula for lateral area of a cone = πrl

Plug in the values

Lateral area of the cone = π*1*2.2

Lateral area = 2.2π m²

✔️ Formula for surface area of a cone = πr(l + r)

Plug in the values

Surface area of the cone = π*1(2.2 + 1)

Surface area = π(3.2)

Surface area = 3.2π m²

The answer would therefore be:

2.2π m² : 3.2π m²

7 0

2 years ago

BRAINLIEST PLEASE HELP np<br> If f(x)=-x^2+6x-1 and g(x)=3x^2-4x-1, find (f+g)(x)

raketka [301]

Answer:

$\large\boxed{B.\ (f+g)(x)=2x^2+2x-2}$

Step-by-step explanation:

$f(x)=-x^2+6x-1\\\\g(x)=3x^2-4x-1\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute:}\\\\(f+g)(x)=(-x^2+6x-1)+(3x^2-4x-1)\\\\(f+g)(x)=-x^2+6x-1+3x^2-4x-1\qquad\text{combine like terms}\\\\(f+g)(x)=(-x^2+3x^2)+(6x-4x)+(-1-1)\\\\(f+g)(x)=2x^2+2x-2$

8 0

3 years ago

Is 0.102 less than 3/7

Bond [772]

it is less than

3/7 ⇒ 0.42857142857

3 0

3 years ago

In ΔUVW, w = 3 inches, ∠W=23° and ∠U=73°. Find the length of u, to the nearest 10th of an inch.

kirza4 [7]

Answer:

<h2>7.4inches</h2>

Step-by-step explanation:

Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.

According to the rule;

$\frac{u}{sinU} = \frac{v}{sinV} = \frac{w}{sinW}\\\frac{u}{sinU} = \frac{w}{sinW}$

Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

$\frac{u}{sin73^{0} } = \frac{3}{sin23^{0} }\\usin23^{0} = 3sin73^{0}\\u = \frac{3sin73^{0} }{sin23^{0} }\\u = \frac{2.87}{0.39} \\u = 7.358\\u = 7.4in$

The length of u is 7.4inches to nearest 10th of an inch

6 0

3 years ago