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xxTIMURxx [149]
3 years ago
14

Connor just switched to a new phone plan. His old phone plan was $10 plus 10 cents per gigabyte of data overage. His new plan is

$12 plus 8 cents per gigabyte of data overage. Connor claims that he is going to pay less on his new plan because he always goes over his data limit. His data overage was 105 gigabytes. Is Connor's claim true?
A- Yes, because 0.10(105) > 0.08(105).
B- Yes, because 10 + 0.10(105) > 12 + 0.08(105).
C- No, because 10 + 0.10(105) < 12 + 0.08(105).
D- No, because 0.10(105) < 0.08(105).
Mathematics
1 answer:
Archy [21]3 years ago
3 0
First, let's write an expression for both plans. We will use x for the data overage in gigabytes.

Old plan: 10 + 0.10x

New plan: 12 + 0.08x

Now let's plug in 105 to the expressions to determine the costs of the plans.

Old plan: 10 + 0.10(105) = $20.50

New plan: 12 + 0.08(105) = $20.40

So yes, Connor was correct because when we compare his plans, the new one costs 10 cents less.

The answer is B.


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Answer:

Step-by-step explanation:

Hello!

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Sample 1 (aqueous film forming foam)

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Sample 2 (alcohol-type concentrates )

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S₂= 0.8

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The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

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