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Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
In 2 years theirs 17520 in total!
Answer:
<u>Please read below.</u>
Step-by-step explanation:
The instructions were followed, horizontal or vertical path and never diagonal:
75 76 81 66 65 14 13 8 7
74 77 80 67 64 15 12 9 6
73 78 79 68 63 16 11 10 5
72 71 70 69 62 17 2 3 4
55 56 57 58 61 18 1 22 23
54 53 52 59 60 19 20 21 24
45 46 51 50 37 36 31 30 25
44 47 48 49 38 35 32 29 26
43 42 41 40 39 34 33 28 27
Answer:
Step-by-step explanation:
The graph will open upwards
Shifted to the right by 5
Vertex: (5,0)
Domain: x= All Real Numbers
Range: y
0
