basketball player who ordinarily makes about 55% of his free throw shots has made 4 in a row. Is this evidence that he has a "ho
1 answer:
Answer:
Step-by-step explanation:
Given that a basketball player who ordinarily makes about 55% of his free throw shots has made 4 in a row.
Probability for a success in any random throw =
Since each throw is independent no of successive throws is binomial with
p = 0.55 and q = 0.45
Probability his free throw shots has made 4 in a row
= Prob that continuous succesees in 4 throws
=
which shows that this is a very rare event with 0.55 for each success.
Hence this is unusual and there is a necessity to increase 0.55 or 55%
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This is how I found the answer
Answer:
p=0.063
Step-by-step explanation:
Let X be number of the certain brand of jelly beans that are made so that each package contains about the same number of beans.
X is N(375, 8)
YOu are collecting a sample size of
n = 8
Findings from the sample
(Left tailed test at 5% level)
Since sample size is small though sigma is known we use Z test, since norm
Mean difference = -5
Std error =
Test statistic t = mean diference / std error =
df = n-1 =5
p value = 0.063