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Daniel [21]
2 years ago
13

How many different four-digit numbers can be formed with the numbers 7; 4; 5; 1; 2; 9; and 8?

Mathematics
2 answers:
ExtremeBDS [4]2 years ago
6 0

Answer:

I believe it's 2401.

Step-by-step explanation:

7 x 7 x 7 x 7 = 2401

salantis [7]2 years ago
4 0

Answer:

2 answers.

Step-by-step explanation:

ANSWER 1: With Repetition

Numbers: 1,2,4,5,7,8

There are 4 digits __ __ __ __

1st digit can be filled by any of the 6 numbers.

Similarly 2nd, 3rd and 4th digits.

Hence each digit will have 6 possibilities.

Therefore no.of 4 digit numbers that can be formed are 6 x 6 x 6 x 6 = 1296

ANSWER 2: Without Repetition

4 digits __ __ __ __

Now the first digit can be filled by any of the six numbers. Therefore there are 6 possibilities

The second digit will have only 5 possibilities as one of the numbers gets used up by the 1st digit.

Similarly the 3rd and 4th digits will have 4 and 3 possibilities respectively.

Therefore no.of 4 digit numbers that can be formed are 6 x 5 x 4 x 3 = 360

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zimovet [89]
Okay, so slope intercept form is y=mx+b. Like a normal problem with numbers, you add or subtract from each side. 
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Step-by-step explanation:

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