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avanturin [10]
3 years ago
7

In the figure drawn below CBD,DBE, m ABE=90 which of the following statements is true?

Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0
<HBF =  <GBF + <HBG

but

 <GBF = <CBD  (vertical angles)
< HBG = <DBE  (vertical angles)


so
<HBF = <CBD  + <DBE

Answer
A.  <CBD  + <DBE = <HBF 
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The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab
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Answer:

the probability that the sample mean will be larger than 1224 is  0.0082

Step-by-step explanation:

Given that:

The SAT scores have an average of 1200

with a  standard deviation of 60

also; a sample of 36 scores is selected

The objective is to determine  the probability that the sample mean will be larger than 1224

Assuming X to be the random variable that represents the SAT score of each student.

This implies that  ;

S \sim N ( 1200,60)

the probability that the sample mean will be larger than 1224 will now be:

P(\overline X > 1224) = P(\dfrac{\overline X - \mu }{\dfrac{\sigma}{\sqrt{n}} }> \dfrac{}{}\dfrac{1224- \mu }{\dfrac{\sigma}{\sqrt{n}} })

P(\overline X > 1224) = P(Z > \dfrac{1224- 1200 }{\dfrac{60}{\sqrt{36}} })

P(\overline X > 1224) = P(Z > \dfrac{24 }{\dfrac{60}{6} })

P(\overline X > 1224) = P(Z > \dfrac{24 }{10} })

P(\overline X > 1224) = P(Z > 2.4 })

P(\overline X > 1224) =1 -  P(Z \leq 2.4 })

From Excel Table ; Using the formula (=NORMDIST(2.4))

P(\overline X > 1224) = 1 -  0.9918

P(\overline X > 1224) = 0.0082

Hence;  the probability that the sample mean will be larger than 1224 is  0.0082

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