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Rina8888 [55]
3 years ago
5

Find the volume of the rectangular prism

Mathematics
2 answers:
user100 [1]3 years ago
8 0
Volume= Length • Width • Height

Given info: 6•8•9= 432cm cubed
Luba_88 [7]3 years ago
5 0

Answer:

○ C 432 cm.³

Step-by-step explanation:

whl = V

432 = (6)(9)(8)

I am joyous to assist you anytime.

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PLS, I'm begging for help, il give the brainiest to who gives me the right answer! THIS IS 30 POINTS
solniwko [45]

Answer:

<em>Similarity doesn't changes angle measures</em>

  • ∠U = 56°, ∠U' = 3x - 16
  • ∠U = ∠U'

a) 3x - 16 = 56 ⇒ 3x = 72 ⇒ x = 24°

b) ∠T = x + 46 = 24 + 46 = 70°

c) <u>Scale factor:</u>

  • k = S'T'/ST = 19/57 = 1/3

<u>Find y using known sides and scale factor:</u>

  • U'V'/UV = 1/3
  • (y + 4)/63 = 1/3
  • y + 4 = 21
  • y = 21 - 4
  • y = 17

8 0
3 years ago
Theo was asked to find the measure of x in the following polygon.
Oliga [24]

Answer:

c, I had gotten it right, if you have any problems then im am very srry tell me if do

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to b
Alina [70]

Answer:

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 28.983051

Chi-square value = χ² = 2.154239

Degree of freedom = 1

Critical value = 3.841

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

Step-by-step explanation:

He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices.

So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles.

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Data collected by Dr. Pagels:

                                              meadow voles     common voles      Row Total

apple slices                                     26                          32                      58

peanut butter-oatmeal                   35                          25                     60

Column Total                                   61                          57                     118

Where 118 is the grand total.

The expected number is given by

Expected = (row total)×(column total)/grand total

Expected meadow vole/apple slices = 58×61/118

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 58×57/118

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 60×61/118

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 60×57/118

Expected common vole/peanut butter-oatmeal = 28.983051

The chi-square statistic value is given by

χ² = Σ(Observed - Expected)²/Expected

χ² = (26 - 29.983051)²/29.983051 + (32 - 28.016949)²/28.016949 + (35 - 31.016949)²/31.016949 + (25 - 28.983051)²/28.983051

χ² = 2.154239

The degrees of freedom is given by

DoF = (row - 1)×(col - 1)

For the given case, we have 2 rows and 2 columns

DoF = (2 - 1)×(2 - 1)

DoF = 1

The given level of significance = 0.05

The critical value from the chi-square table at α = 0.05 and DoF = 1 is found to be

Critical value = 3.841

Conclusion:

Reject H₀ If χ² > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

For the given case,

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

8 0
3 years ago
How to solve 5(x+1)(x+1)(x+7)
damaskus [11]
Distribute the 5 to each of the numbers so you should get 5x+5+5x+5+5x+35. after this you should combine like terms, all of the 5’s & the 35 and 5x’s. you should have 15x+45. then you divide 45 by the 15 and you should get x=3
8 0
3 years ago
The function p(x) = - 2(x-9)2 + 100 is used to determines the profit on T-shirts sold for x dollars. What would the profit from
dolphi86 [110]

ANSWER

$28

EXPLANATION

The profit function is given as:

p(x) =  - 2 {(x - 9)}^{2}  + 100

where x is the price of the T-shirt in dollars.

To find the profit on a T-shirt whose price is $15, we substitute x=15 into the function and simplify.

p(15) =  - 2 {(15 - 9)}^{2}  + 100

We simplify to get:

p(15) =  - 2 {(6)}^{2}  + 100

p(15) =  -72+ 100

p(15) =  28

6 0
3 years ago
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