For part a,
y < x
y > -2x
Point B: (3,1) plugin x=3, y=1 y < x 1 < 3
which is true, so point B satisfies the first inequalityYou can graph the inequality y > 2x+5 and see which schools are in the shaded region
Tangent theta = opp/adj = 48/36 = 4/3
-12 + 18 = 70 - 64 or(-12+18)+(6*12)-2
Given the graph of the function

and the graph of the function


when f(x) = g(x).
This occurs at the point(s) of intersection of the graphs of the function f(x) and g(x).
From the graph, we can approximate the points of intersection of the graphs of the function f(x) and g(x) to pe points
(-1.9, 13.7) and (2.7, 0).
Y - 10 =(-1/3) ( X - 10 )
Y = ( -1/3) X + ( 40/3)
Step-by-step explanation:
Step 1:
The basic form of Slope Intercept equation is

Step 2:
Points are (10,10) and m=-1/3
Y-10 = (-1/3)(X-10)
Y = ( (-X + 10 )/3) + 10
Y =( - X / 3 ) +( 40 / 3)