Answer:
the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Step-by-step explanation:
Given the data in the question;
Feeder 1 2 3 4
Observed visits;
60 90 92 58
data sample = 300
Expected
= 300 / 4 = 75
the x² test statistic = ?
= ∑[ (
-
)²/
]
= [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
= [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
= 13.7066 ≈ 13.71
Therefore, the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Answer:
the hell you are talking about?
Step-by-step explanation:
Answer:
Option 2) Null hypothesis: p = 0.078
, Alternate hypothesis: p > 0.078
Step-by-step explanation:
We are given the following in the question:
According to the National Center of Health Statistics, about 7.8% of all babies born in the U.S. are categorized as low birth weight.
Sample size, n = 1200
p = 7.8% = 0.078
We have to carry a hypothesis test whether national percentage is higher than 7.8% or not.
Thus, we can design the null and the alternate hypothesis

Thus, the correct answer is:
Option 2) Null hypothesis: p = 0.078
, Alternate hypothesis: p > 0.078