Answer:
![y=(x+3)^2-1\\y=x^2+6x+8](https://tex.z-dn.net/?f=y%3D%28x%2B3%29%5E2-1%5C%5Cy%3Dx%5E2%2B6x%2B8)
Step-by-step explanation:
Given:
Vertex of the parabola is, ![(h,k)=(-3,-1)](https://tex.z-dn.net/?f=%28h%2Ck%29%3D%28-3%2C-1%29)
Equation of the parabola in vertex form is given as:
![y=(x-h)^2+k](https://tex.z-dn.net/?f=y%3D%28x-h%29%5E2%2Bk)
Plug in
. This gives,
![y=(x-(-3))^2+(-1)\\y=(x+3)^2-1](https://tex.z-dn.net/?f=y%3D%28x-%28-3%29%29%5E2%2B%28-1%29%5C%5Cy%3D%28x%2B3%29%5E2-1)
Therefore, the equation of the given graph is
.
Answer:
Step-by-step explanation:
y intercept is <u>8.53 hrs</u>
-0.73(4) + 8.53 = <u>5.61 hrs</u>
slope is -<u>0.73 hr</u>
f(x)= -2x-3
Step-by-step explanation:
Step 1:
Let the sequence given here is -5, -7, -9, -11, -13 ......
Here the first term (a₁) of sequence is -5
And the common difference between the numbers in the sequence is
d= (-7-(-5)) = -7+5 = -2
Let the number of terms be x
Step 2;
To find the sequence function basic arithmetic sequence formula is
aₙ = a₁ + d( x-1)
Applying the values we get
f(X) = -5 + ((-2)(X-1))
on simplification
f(X) = -5 + (-2X+2)
f(X)= -5+2-2X
f(X)= -3-2X
Let's x represents the first odd integer
The next consecutive integer would be represented as x+2.
So x and x+2 being multiplied together will give us 1443:
(x)(x+2)=1443
x^2+2x=1443
x^2+2x-1443=0
By solving the quadratic equation using the quadratic formula, x will equal to 37 and -39.
Since the problem says "integers", so I'm assuming two pairs of consecutive integers would be ok.
With that said you 1st pair will be: 37,39
Your second pair will be: -37,-39.
The length and width of the rectangle are: ![2x^2y^2 , 3xy^3](https://tex.z-dn.net/?f=2x%5E2y%5E2%20%2C%203xy%5E3)
<h3>What is the area of the rectangle?</h3>
The area of the rectangle is the product of the length and width of a given rectangle.
The area of the rectangle = length × Width
The area of a rectangle is represented by the expression
.
The area of the rectangle = ![2x^2y^2 \times 3xy^3](https://tex.z-dn.net/?f=2x%5E2y%5E2%20%5Ctimes%203xy%5E3)
= ![6x^3y^5](https://tex.z-dn.net/?f=6x%5E3y%5E5)
So, the length and width of the rectangle are: ![2x^2y^2 , 3xy^3](https://tex.z-dn.net/?f=2x%5E2y%5E2%20%2C%203xy%5E3)
Learn more about the area;
brainly.com/question/1658516
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