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lisov135 [29]
4 years ago
6

PLEASE HELP Is this ordered pair a solution to this inequality. (1,3) x + y + < 10

Mathematics
1 answer:
ipn [44]4 years ago
3 0

Answer:

Step-by-step explanation:

hello :

(1,3)  is solution for    x + y  < 10 because when x=1 and y=3

1+3< 10 ....right

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In Exercise, find the derivative of the function.<br> y = 3ex - xex
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Answer:

the question is incomplete, the complete question is "find the derivative of the function y=3e^{x}-xe^{x}"

answer: \frac{dy}{dx}=(2-x)e^{x}.

Step-by-step explanation:

From the equation,  y=3e^{x}-xe^{x}, we approach the question using the differentiation of a product and differentiation of a sum simultaneously,

the differentiation of a sum is express as

f(x)=u(x)+v(x)+.....w(x) then

\frac{df(x)}{dx}=\frac{du(x)}{dx}+\frac{dv(x)}{dx}+...\frac{dw(x)}{dx}.\\

For the differentiation of a product we have

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\frac{df(x)}{dx}=\frac{dv(x)}{dx}u(x)+\frac{du(x)}{dx}v(x)

hence if we go by the formula we arrive at

for   y=3e^{x}

let u(x)=3 hence du/dx=0 and

v(x)=e^{x} and \frac{dv(x)}{dx}=e^{x}

hence \frac{dy}{dx}=3e^{x}+0e^{x}\\\frac{dy}{dx}=3e^{x}---equation 1\\

Also for y=-xe^{x}\\\frac{dy}{dx}=-e^{x}-xe^{x}---equation 2.

if we add equation 1 and equation 2 we arrive at

\frac{dy}{dx}=3e^{x}-e^{x}-xe^{x}\\\frac{dy}{dx}=(3-1-x)e^{x}\\\frac{dy}{dx}=(2-x)e^{x}.

4 0
3 years ago
Given that x is an even number, express, in terms of x, the product of the next two odd numbers.
wariber [46]

Answer:

Odd is the answer.

Step-by-step explanation:

An even number can be written in the form 2x, where x is an integer.

An odd number can be written in the form 2x + 1, where x is an integer.

So two odd numbers can be represented by 2a +1 and 2b +1, the product would be:

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So (2a + 1)(2b + 1) = 2(2ab + a + b ) + 1 = 2x +1 which is odd.

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3 years ago
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The Correct choice is :

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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