2y² + y - 3
(2y+3)(y-1)
2y(y-1) + 3(y-1)
2y² - 2y + 3y - 3
2y² + y - 3
2y + 3 = 0
2y = -3
y = -3/2
y = -1 1/2
y - 1 = 0
y = 1
2y² + y - 3 = 0
2(-3/2)² + (-3/2) - 3 = 0
2(9/4) - 3/2 - 3 = 0
18/4 - 3/2 - 3 = 0
18/4 - (3/2 * 2/2) - 3(4/4) = 0
18/4 - 6/4 - 12/4 = 0
(18 - 6 - 12)/4 = 0
(18 -18)/4 = 0
0/4 = 0
0 = 0
Answer:
The answer is C. m<1=60 degrees m<2=30 degrees and m<3 equals 60 degrees
Step-by-step explanation: So, if 1 was 60 degrees then half of it is 30 degrees which is the angle for two. Them 3 is the same degree as 1.
<u>ANSWER</u>
True
<u>EXPLANATION</u>
The given trigonometric equation is
Recall the double angle identity:
We apply this identity to obtain:
We maintain the LHS and simplify the RHS to see whether they are equal.
Expand the parenthesis
Recall that:
We apply these identities to get:
Also
Therefore the correct answer is True
X = 34
<span>2+8-x=-24
</span>Add 2 + 8: 10-x=-24
Subtract 10 from each side: -x = -34
Change the signs from each side: x = 34
Answer: sec (0) tan (0)
Step-by-step explanation:
The instructions that you've provided were kind of obscure to me, so I did the best I could do. The answer above is what I believe the answer is.
