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3 years ago

Plz help.. I asked this question on English, but no one answered.

Mathematics

1 answer:

enyata [817]3 years ago

4 0

Answer:

Step-by-step explanation:

A. abject - 2. wretched

B. congenial - 6. friendly

C. deliberately - 7. thoughtfully

D. impetuous - 3. impulsive

E. misgiving - 4. doubt

F. perturbation - 5. disturbance

G. pervade - 8. permeate

H. transgress - 1. err

Hope this helps :)

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Paul has $78 in the bank and saves $30 each week. What is the initial value? Be sure to use negative signs if needed.

marin [14]

Answer:

The initial value is $78

Step-by-step explanation:

Given

$Base\ Amount = \$78$

$Additional = \$30$ (weekly)

Required

Determine the initial value

The initial value is the amount he has in its bank account before making his weekly savings.

From the question, we have that his initial balance is $78.

Hence, the initial value is $78

However, his weekly balance can be expressed as:

$Balance = Base\ Amount + Additional * number\ of weeks$

Represent number of weeks with x; So, we have:

$Balance = 78 + 30 * x$

$Balance = 78 + 30 x$

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2 years ago

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2 years ago

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A bowling ball has a diameter of 8.5 inches. What is its approximate volume?

Alex Ar [27]

Answer:

321.56

Step-by-step explanation:

volume = (4/3) * π * r³

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2 years ago

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victor needs 30 feet of rope. the rope he want to buy is sold by the yard. he know that there are 3 feet in the 1 yard. how many

solmaris [256]

Answer: 10 yards

Step-by-step explanation:

Covert 30 feet into yards to find how many yards he should buy.

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3 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

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3 years ago