False, they would be called Complementary
Answer:
∫₂⁵ ln(x) dx
Step-by-step explanation:
lim(n→∞) ∑ᵢ₌₁ⁿ (3/n) ln((2n + 3i) / n)
lim(n→∞) ∑ᵢ₌₁ⁿ (3/n) ln(2 + (3/n) i)
The width of the interval is b−a = 3, and there are n rectangles. So the width of each rectangle is 3/n, and the height of each rectangle is ln(2 + (3/n) i).
The ith term is 2 + (3/n) i, so a = x₀ = 2. Therefore, b = 2+3 = 5.
So the region is the area under f(x) = ln(x) between x=2 and x=5.
∫₂⁵ ln(x) dx
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, … these are the
Fibonacci numbers.
so add in +1,
we get
1+1,1+1,2+1, 3+1 ,5+1, 8+1 ,13+1, 21+1, 34+1, 55+1 ...........
2,2,3,4,6,9,14,22,35,56.........
so 22,35,56 is the answe
dont delete my answer again