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Natalija [7]
3 years ago
11

Graph the linear equation by finding and plotting its intercept. -x+2y=6

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

y-intercept: (0,3)

x-intercept: (-6,0)

Step-by-step explanation:

put equation into y=mx+b

-x+2y=6      (add x to both sides)

2y=6+x      (divide both sides by 2)

y=.5x+3

find y-intercept

       set x=0

   solve for y, y=3

y-intercept (0,3)

find x-intercept

       set y=0

    solve for x, x=-6

x-intercept (-6,0)

graph and table confirm values

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Step-by-step explanation:

Let 'x' be the original price.

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The coordinates of three of the vertices of parallelogram ABCD are A(1, 0), B(2, 3), C(3, 2). What are coordinates of the fourth
nalin [4]

Answer:

 A) The coordinates of the fourth vertex are:

1) x-coordinate:

x=2

2) y-coordinate:

y=-1

B) The point of intersection of the diagonals is:  (2,1)

Step-by-step explanation:

We need to remember that the diagonals of a parallelogram intersect each other at a half-way point and the midpoint of each diagonal is the same.

The midpoint formula is:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Since:

M_{AC}=M_{BD}

We can find the coordinates of the fourth vertex D(x,y) through these procedure:

1) x-coordinate:

\frac{1+3}{2}=\frac{2+x}{2}\\\\2(2)=x\\\\4-2=x\\\\x=2

2) y-coordinate:

\frac{0+2}{2}=\frac{3+y}{2}\\\\1(2)-3=y\\\\y=-1

Therefore,  fourth vertex is D(2,-1)

Since the point of intersection of the diagonals is the midpoint of a diagonal (Remember that  M_{AC}=M_{BD}), this is:

M_{AC}=M_{BD}=(\frac{1+3}{2},\frac{0+2}{2})\\\\M_{AC}=M_{BD}=(2,1)

Therefore, the point of intersection of the diagonals is (2,1)

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