(a)36 = 6
(b)81 = 9
(c)256 = 16
(d)196 = 14
Answer:
190 students
Step-by-step explanation:
Set up a proportion:
95/100 = x/200
Cross multiply:
100x = 19000
Simplify:
x = 190 students
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
<h3>What is the numerical value of DE?</h3>
Given the data in the question;
- E is a point between point D and F.
- Segment DF = 78
- Segment DE = 5x - 9
- Segment EF = 2x + 10
- Numerical value of DE = ?
Since E is a point between point D and F.
Segment DF = Segment DE + Segment EF
78 = 5x - 9 + 2x + 10
78 = 7x + 1
7x = 78 - 1
7x = 77
x = 77/7
x = 11
Hence,
Segment DE = 5x - 9
Segment DE = 5(11) - 9
Segment DE = 55 - 9
Segment DE = 46
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
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Answer:
f(6) = 24
Step-by-step explanation:
f(x) = x^2 - 2x
Let x = 6
f(6) = 6^2 - 2(6)
= 36 - 12
= 24