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Helga [31]
3 years ago
14

What is the height of the triangles?

Mathematics
2 answers:
krok68 [10]3 years ago
6 0
The highest triangle is 7
andriy [413]3 years ago
5 0

Answer:

the  answer is 7

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Test the four possible vertices that you found in the objective function in part A. Use those values to determine which set of v
irga5000 [103]

The testing of the four vertices of the objective function gives;

C(5, 0, 55) = 430

C(5, 30, 25) = 400

C(15, 30, 15) = 420

C(45, 0, 15) = 510 (maximum)

<h3>How to test objective functions?</h3>

The objective function is seen as attached.

Now, it is noticed that just two of the vertices are listed. The other two vertices are intersections of x + y + z = 60 with x = 5 and the constraints on y.

We will assume that; 0 ≤ y ≤ 30

Thus, the missing vertices are;

(x, y, z) = (5, 0, 55)  and  (5, 30, 25)

The two given vertices are;

(x, y, z) = (15, 30, 15)  and  (45, 0, 15)

Therefore, the objective function values are;

C(5, 0, 55) = 9·5 +6·0 +7·55 = 45 +0 +385 = 430

C(5, 30, 25) = 9·5 +6·30 +7·25 = 45 +180 +175 = 400

C(15, 30, 15) = 9·15 +6·30 +7·15 = 135 +180 +105 = 420

C(45, 0, 15) = 9·45 +6·0 +7·15 = 405 +0 +105 = 510

Read more about Objective Functions at; brainly.com/question/16826001

#SPJ1

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Need help with the question, I already have the degree and leading coefficient but not the constant term for this polynomial. f(
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