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ankoles [38]
3 years ago
13

Range of scores making up the interquartile ranger

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0

For a standard normally distributed random variable <em>Z</em> (with mean 0 and standard deviation 1), we get a probability of 0.0625 for a <em>z</em>-score of <em>Z</em> ≈ 1.53, since

P(<em>Z</em> ≥ 1.53) ≈ 0.9375

You can transform any normally distributed variable <em>Y</em> to <em>Z</em> using the relation

<em>Z</em> = (<em>Y</em> - <em>µ</em>) / <em>σ</em>

where <em>µ</em> and <em>σ</em> are the mean and standard deviation of <em>Y</em>, respectively.

So if <em>s</em> is the standard deviation of <em>X</em>, then

(250 - 234) / <em>s</em> ≈ 1.53

Solve for <em>s</em> :

16/<em>s</em> ≈ 1.53

<em>s</em> ≈ 10.43

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By SSS congruency criteria ΔABC ≅ ΔDEF

<h3>What is congruency?</h3>

Two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.

The given vertices of the triangles are;

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The lengths of the sides of ΔABC are

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Learn more about this concept here:

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