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bija089 [108]
3 years ago
10

H varies directly to the cube of c. When H = 40, C = 2. (a) Express H in terms of c.

Mathematics
1 answer:
Alecsey [184]3 years ago
4 0

Answer:

H in terms of c is H = 5c³.

Step-by-step explanation:

Given that:

H = 40 and c = 2

H varies directly to the cube of c.

Which means that,

H ∝ c³

Let,

k be the proportionality constant.

H = kc³

Putting H=40 and c=2

40=k(2)^3\\40=k(8)\\40=8k\\8k=40

Dividing both sides by 8,

\frac{8k}{8}=\frac{40}{8}\\k=5

Now,

H in terms of c.

H = 5c³

Hence,

H in terms of c is H = 5c³.

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Sophie [7]

Answer: Okay first think back you surely have divided whole numbers by 10 it is the same with decimals for each 0 in the thing you are dividing it by you move the dot one to the left. So if you divide it by 10 it is 5.356 by 100 it would be 0.5356.

Hence the answer is 5.356.

Step-by-step explanation:

Hope it helps

4 0
3 years ago
A radio station ordered hats and coffee mugs to give away as prizes. A total of 1,000 of these items were ordered, and 3 times a
marshall27 [118]

Answer:

The options are not shown, so i will answer in a general way.

Let's define the variables:

h = number of hats

m = number of mugs.

We know that a total of 1000 items were ordered, then:

h + m = 1000

We also know that we have 3 times more mugs than hats, this can be written as:

m = 3*h

Now we have the system of equations:

h + m = 1000

m = 3*h

To solve these, we usually start by isolating one of the variables in one equation and then replace that in the other equation, but in this case, we already have m isolated in the second equation, then we can replace that in the first equation to get:

h + m = 1000

h + (3*h) = 1000

Now we can solve this equation for h, and find the number of hats ordered.

4*h = 1000

h = 1000/4 = 250

There were 250 hats ordered.

3 0
3 years ago
50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

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3 years ago
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Talja [164]

Answer:

The answer is C

Step-by-step explanation:

7 0
3 years ago
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HELP WILL MARK BRAINLIEST ANSWERRRRRR IF GOTTEN RIGHT
pentagon [3]
B hope that is correct answer
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3 years ago
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