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bija089 [108]
3 years ago
10

H varies directly to the cube of c. When H = 40, C = 2. (a) Express H in terms of c.

Mathematics
1 answer:
Alecsey [184]3 years ago
4 0

Answer:

H in terms of c is H = 5c³.

Step-by-step explanation:

Given that:

H = 40 and c = 2

H varies directly to the cube of c.

Which means that,

H ∝ c³

Let,

k be the proportionality constant.

H = kc³

Putting H=40 and c=2

40=k(2)^3\\40=k(8)\\40=8k\\8k=40

Dividing both sides by 8,

\frac{8k}{8}=\frac{40}{8}\\k=5

Now,

H in terms of c.

H = 5c³

Hence,

H in terms of c is H = 5c³.

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6 0
2 years ago
Please Help Me!!!!! The displacement of a particle d (in km) as a function of time t (in hours) is given by: d(t) = 2t^3 + 5t^2
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