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3 years ago

12

Legal descriptions tend to prefer neat straight lines from point to point, regardless of describing a square, rectangle, triangl

e or even a smooth circle. When might a property boundary end up being a squiggly line?

1 answer:

julia-pushkina [17]3 years ago

5 0

Answer:

When describing a property line drawn down the center of a creek bed

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which one of the following statements express a true proportion a.42:7=6:2 b.14:6=28:18 c. 3:5=12:20 d.2:3=3:2

Drupady [299]

C.) 3:5 = 12:20
It is this because you can divide them evenly into each other. 3*4 is 12 and if you do 5*4 it is 20. Boo yeah

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3 years ago

Find the area of segment CED given the following information:

Hitman42 [59]

Area of sector CAD = 72 / 360 x pi x 6^2 = 7.2pi = 22.6195 in^2

Therefore, area of segment CED = 22.6195 - 17.18 = 5.44 in^2

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3 years ago

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Solve for x: x/3= 7<br><br> x= 21<br> x= 12<br> x= 7/3<br> x= 11

myrzilka [38]

Answer:

7÷3=2 1/3...

×=7/3...

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3 years ago

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For nitrogen to be a liquid, its temperature must be within 12.78 °F of –333.22 °F. Which equation can be used to find the maxim

ziro4ka [17]

To determine the maximum and minimum temperatures at which nitrogen remains a liquid, use the equation |x - (-333.32)| = 12.78, where x is equal to the maximum and minimum temperatures. Using this equation, the maximum temperature is -320.54 degrees Fahrenheit while the minimum is -346.10 degrees Fahrenheit.

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3 years ago

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Suppose the mean SAT verbal score is 525 with a standard deviation of 100, while the mean SAT math score is 575 with a standard

Ipatiy [6.2K]

Answer:

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

Step-by-step explanation:

Normal variables

Normal variables have mean $\mu$ and standard deviation $\sigma$

When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.

In this question:

Verbal: $\mu_{V} = 525, \sigma_{V} = 100$ .

Math: $\mu_{M} = 575, \sigma_{M} = 100$

Combined:

$\mu = \mu_{V} + \mu_{M} = 525 + 575 = 1100$

$\sigma = \sqrt{\sigma_{V}^{2}+\sigma_{M}^{2}} = \sqrt{100^2 + 100^2} = 141$

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

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3 years ago