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ch4aika [34]
3 years ago
14

A large garden has a set of underground sprinklers. Suppose the center of the garden is located at the origin of a grid with int

ervals measured in feet. One sprinkler is positioned at (2, 4) and reaches a radius of 8 feet. The second sprinkler is positioned at (–6, –4) and reaches a radius of 6 feet. The system of inequalities represents this scenario.
Which location is in the region for plants receiving the maximum amount of water?

(–3, –1)
(–7, 1)
(1, –5)
(2, 1)

Mathematics
2 answers:
Klio2033 [76]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Got it right edge2021

alexgriva [62]3 years ago
3 0

Answer:

D. (2,1)

Step-by-step explanation:

I just did the quiz and got it right edg21

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Cara is 14 years old . This is twice as old as her brother . How old is her brother
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A manufacturer knows that their items have a normally distributed length, with a mean of 15.4 inches, and standard deviation of
Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that \mu = 15.4, \sigma = 3.5

16 items are chosen at random

This means that n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16.8 - 15.4}{0.875}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

5 0
3 years ago
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cupoosta [38]
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Explanation: 7×6 = 42 so to get W you have to multiply 3 by 6. 3×6 = 18.
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2 years ago
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I need help please :)))
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Answer:

\mathrm {7.1 \: inches}

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Circumference of a circle is \pi d

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