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Answer: 
Step-by-step explanation:
Transformation rule for dilation:
, where k = scale factor
Given : Scale factor = 
Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)
Vertices after dilation:




Hence, the coordinates of the image if the parallelogram = 
Answer:
http://www.ametys.ma/sites/default/files/webform/10_0.html
http://www.ametys.ma/sites/default/files/webform/zdfzxt.html
http://www.ametys.ma/sites/default/files/webform/srdst12.html
http://www.ametys.ma/sites/default/files/webform/13_0.html
http://www.ametys.ma/sites/default/files/webform/14_0.html
http://www.ametys.ma/sites/default/files/webform/06_0.html
Step-by-step explanation:
Answer:
i)W = 2500 / T
ii) W = 500 Tons
iii) grad W(10°) = - 25î
iv) The formulation is not practical
Step-by-step explanation:
i) Write an equation describing the use of coal
As use of coal is inversely proportional to the average monthly temperature
if W is use of coal in tons/per month then
W(t) = k / T where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions
k = ?? we know that when T = 25° W = 100 tons the by subtitution
W = k/T 100 = k /25 k = 2500 Tons*degree
Then final equation is:
W = 2500 / T
ii) Find the amount of coal when T = 5 degrees
W = 2500 / 5
W = 500 Tons
iii)
The inverse proportionality implies that W will decrease as T increase.
The vector gradient of W function is:
grad W = DW(t)/dt î
grad W = - 2500/T² î
Wich agrees with the fact that W is decreasing.
And when T = 100°
grad W(10°) = - 2500/ 100 î ⇒ grad W(10°) = - 25î
iv) When T = 0 The quantity of coal tends to infinite and the previous formulation is not practical
Answer:
$135
Step-by-step explanation:
Paperback=$4.75
Hardcover=$11.50
Multiply 4.75 and 20=95
Multiply 11.50 and 20=230
Subtract 230 and 95=135
so it would be $135