We have that

H(t)=-4.9t²<span>+50t + 2

we know that
</span><span>The initial height of the rocket, in meters is for t=0 sec
fot t=0
H(t)=</span>-4.9*0²+50*0 + 2------> H(t)=2 m

the answer is
The initial height of the rocket is 2 m

4 0

3 years ago

Write -72=2y^2-16y-20x in standard form

kifflom [539]

Answer:

-72=-12y-20x

Step-by-step explanation:

-72=2y^2-16y-20x

square the 2 keeping the variable

-72=4y-16y-20x

Then combine like terms in this case the numbers followed by y's

-72=-12y-20x

This is the standard form as there is nothing else you can combine to break this down any further

5 0

3 years ago

Read 2 more answers

Describe a real-life problem that has the given rate and intercepts. Draw a line that represents the problem. (don´t know what i

gavmur [86]

Answer:

thanks for the points

Step-by-step explanation:

also

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8 0

3 years ago

Read 2 more answers

8313.81=3000(1+r/12)^60 how do you get rid of the exponet

nika2105 [10]

Raise both sides to $\dfrac1{60}$ .

$8313.81=3000\left(1+\dfrac r{12}\right)^{60}$
$\implies8313.81^{1/60}=3000^{1/60}\left(\left(1+\dfrac r{12}\right)^{60}\right)^{1/60}$
$\implies1.162=1.143\left(1+\dfrac r{12}\right)$

$\implies r\approx0.1995$

8 0

3 years ago