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Anni [7]
3 years ago
8

Achariya is lost. She quickly scans the crowd and decides to ask an elderly woman for directions because she believes the woman

will be kind. Which method of problem solving did achariya most likely use?.
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:

representative heuristics

Step-by-step explanation:

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umka21 [38]
Infinite..................
3 0
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H

Step-by-step explanation:

Once graphed, the line passes through (-4,2) while the others do not

7 0
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HURRY PLEASE!! Evaluate the expression below.
tatuchka [14]

Answer:

A

Step-by-step explanation:

Given

20 - ||  - 13 | + 17 |

Note the absolute value function always returns a positive value, that is

| - a | = | + a | = a, thus

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6 0
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Read 2 more answers
Prove that the roots of x2+(1-k)x+k-3=0 are real for all real values of k​
masha68 [24]

Answer:

Roots are not real

Step-by-step explanation:

To prove : The roots of x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0 are real for all real values of k ?

Solution :

The roots are real when discriminant is greater than equal to zero.

i.e. b^2-4ac\geq 0b

2

−4ac≥0

The quadratic equation x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0

Here, a=1, b=1-k and c=k-3

Substitute the values,

We find the discriminant,

D=(1-k)^2-4(1)(k-3)D=(1−k)

2

−4(1)(k−3)

D=1+k^2-2k-4k+12D=1+k

2

−2k−4k+12

D=k^2-6k+13D=k

2

−6k+13

D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))

For roots to be real, D ≥ 0

But the roots are imaginary therefore the roots of the given equation are not real for any value of k.

6 0
3 years ago
If f(x) = 3x-2 and g(x) = 2x + 1 find (f-g)(x)
Marat540 [252]

Answer:

x-3

Step-by-step explanation:

f(x) = 3x-2

g(x) = 2x + 1

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Distribute the minus sign

          =3x-2-2x-1

Combine like terms

        = 3x-2x-2-1

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6 0
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