Please help me with this question

(Fill in the blank) ____ two points are collinear. A. Any B. No C. Sometimes

Zigmanuir [339]

Any two points are collinear.

<h3>Further explanation</h3>

All points in a straight line are called collinear. The two points are always collinear because we can continue to connect them in a straight line.
Therefore, at least two points can form a line and are considered collinear.
All points can, also, be said to be coplanar. This is because in addition to these points forming a line they must also lie on a planar surface.
Noncollinear points are the points that do not lie in a similar straight line.

Let us practice other alternative questions.

(Fill in the blank) ____ three points are collinear.

A. Any

B. No

C. Sometimes

The answer:

Sometimes three points are collinear.

Three points may be collinear or not. We can consider a triangle consisting of three points that are not collinear. All triangle vertices are called coplanar.

<h3>Learn more</h3>

Which points are coplanar and noncollinear? brainly.com/question/4165000
What are the names of three collinear points? brainly.com/question/5191341
Comparing collinear points and coplanar points. brainly.com/question/1593959
Which defines a Line segment? brainly.com/question/909890

Keywords: fill in the blank, any two points are collinear, no, sometimes, connect them, straight line, at least, a planar surface, three points, not, a triangle, vertices, coplanar,

4 0

3 years ago

(20pts=5pts each) For parts (a)–(d) answer the questions and complete the statements in the space provided: line EC ∩ line AC ∩

Lyrx [107]

Answer:

Step-by-step explanation:

Since you didn't state what you're looking for, I will lost out all the angles in the picture instead.

Given that

∠CEF = 150°

∠ECA = 32°

∠CEA = 180 - ∠CEF(angles in a straight line)

∠CEA = 180 - 150

∠CEA = 30°

∠EAC = 180 - ∠CEA - ∠ECA(angles in a triangle)

∠EAC = 180 - 30 - 32

∠EAC = 118°

∠CAB = 180 - ∠EAC(angles in a triangle)

∠CAB = 180 - 118

∠CAB = 62°

∠ACB = ∠CEA = 30°(similar angles)

∠ABC = 180 - ∠CAB - ∠ACB(angles in a triangle)

∠ABC = 180 - 62 - 30

∠ABC = 88°

∠ECB = ∠ECA + ∠ACB(angles in a triangle)

∠ECB = 32 + 30

∠ECB = 62°

∠CEA + ∠ECB + ∠ABC = 180

30 + 62 + 88 = 180°.

Please give brainliest if it helped you <3

5 0

3 years ago

Find the square root of the following: <br>a. 1434/25<br>

ValentinkaMS [17]

Answer:

7.57363849

Step-by-step explanation: square root of 57.36 = 7.57363849

5 0

3 years ago

Read 2 more answers

2 ^ x = 3 ^ (x + 1) solve for x

xenn [34]

Answer:

-2.71

Step-by-step explanation:

This exponential equation can be solved by rewriting it so there is only one base, then using logarithms.

__

<h3>solve for x</h3>

2^x = 3^(x+1) . . . . . given

2^x = 3·3^x . . . . . . eliminate the constant in the exponent

(2/3)^x = 3 . . . . . . . divide by 3^x

x·log(2/3) = log(3) . . . . take logarithms

x = log(3)/log(2/3) ≈ -2.7095113

The value of x is about -2.71.

__

<em>Alternate solution</em>

Taking logarithms transforms this exponential equation to a linear equation.

x·log(2) = (x +1)·log(3) . . . . take logs

x(log(2) -log(3)) = log(3) . . . . . . subtract x·log(3)

x = log(3)/(log(2) -log(3)) = log(3)/log(2/3) . . . . . same result as above

_____

<em>Additional comment</em>

In the attached, we have used a graphing calculator to find the x-intercept of the function f(x) = 0, where f(x) = 2^x -3^(x+1). This is the solution to the given equation.

The applicable rules of logarithms are ...

log(a^b) = b·log(a)

log(a/b) = log(a) -log(b)

5 0

2 years ago

Write two expressions where the solution is 28

Likurg_2 [28]

24 + 4 = 28
14 • 2 = 28
11 • 2.57 = about 28

Hope this helps a little!

8 0

3 years ago