Please help me I’ll give brainly
2 answers:
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Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.
- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )
E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
Answer:
D.
Step-by-step explanation:
The equation given takes the point-slope form which is, . Where,
(a, b) = (x, y) coordinates of a point on the line.
m = slope of the line .
To find which graph has a line equation of , look for the points which will give you something almost exactly as the equation if you substitute their values into
.
Let's consider option D.
We have a given point (1, 2). a = 1, b = 2.
Substitute these into
We have:
As you can see, this looks almost exactly as
.
If you want to be certain that option D is the answer, find m by using the coordinates of any other point on the line and plug into to find m:
In graph D, let's take the points (0, -1)
Divide both sides by -1
3 = m
m = 3.
Therefore, option D is the graph of the line .