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3 years ago

What is the equation of this cricle?

Mathematics

1 answer:

goblinko [34]3 years ago

3 0

Answer:

$\huge\boxed{B.\ x^2+(y-3)^2=16}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

where

$(h,\ k)$ - center

$r$ - radius

From the graph we have

center - (0, 3) → h = 0, k = 3

radius - r = 4

Substitute:

$(x-0)^2+(y-3)^2=4^2\\\\x^2+(y-3)^2=16$

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A cartoonist has 150 pieces of original

Shtirlitz [24]

At most there could be 40 contest winners. If 30 go to publishers he’s left with 120. if each winner can get 3 pieces of work, divide how much artwork he has(120) by the minimum amount of artwork he sends to a winner(3), and you get 40. there could be less depending on if he sends 5 pieces, for example, as a bonus for random winners. The max amount of winners he can have is 40.

4 0

4 years ago

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Brian is standing on a platform that is 4 feet above the surface of a pool. He jumps into the pool and reaches a depth of 7 feet

Licemer1 [7]

Answer:

7×4=28

Step-by-step explanation:

hope this helps you out

5 0

3 years ago

the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?

olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be $\frac{123}{40}$

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= $\frac{-3y}{y-1}$

Similarly fourth term will be

x-3y-2y=x-5y

$x-5y=\frac{x}{y}$

substitute the value of x in the equation

$\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0$

Split the middle term and factorize it

$5y^{2}+3y-5y-3=0\\y(5y+3)-1(5y+3)=0\\$

(y-1)(5y+3)=0

$y=1,\frac{-3}{5}$

y cannot be equal to 1, because the third term and fourth term will become x.

$y=\frac{-3}{5}$

substitute the value of y in the equation of x
$x=\frac{-3y}{y-1} \\=\frac{-3\frac{-3}{5} }{\frac{-3}{5}-1 }\\ =\frac{-9}{8}$

The fifth term= $\frac{x}{y}+(-2y)=\frac{x}{y} -2y$

$\frac{\frac{-9}{8} }{\frac{-3}{5} }-2\frac{-3}{5} =\frac{123}{40}$

Hence, when the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be $\frac{123}{40}$

Learn more about Arithmetic sequence here

brainly.com/question/15412619

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5 0

2 years ago

Order the fractions and decimals from least to greatest.Need help ASAP!!!

Free_Kalibri [48]

32. 2 1/9, 2.17, 2.3

33. 0.1, 0.3, 3/8

8 0

4 years ago

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What is AE ? <br><br> Enter your answer in the box. <br><br> units

maxonik [38]

We know that

side AB is parallel to side CD
then
∠A=∠D
∠B=∠C
therefore
(2x+6)/10=(x+6)/8-------------> 8*(2x+6)=10*(x+6)------> 16x+48=10x+60

16x-10x=60-48----------> 6x=12---------> x=2

so

AE=2x+6-------> 2*2+6--------> AE=10

the answer is AE=10 units

6 0

3 years ago

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