Answer:
x = -5/3
y = 10/3
Step-by-step explanation:
y = x+5
y = -2x
y = x+5
-2x = x + 5
-3x = 5
x = -5/3
y = x+5
y = -5/3 + 5
y = 10/3
Answer:
3/10
Step-by-step explanation:
Just multiply all of the numerators (top numbers) and then multiple all of the denominators (bottom numbers)
2/3x3/4x3/5 would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor. I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers. I will choose 3. I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10
120° will be found on in the second quadrant of the unit circle. Specifically, the reference angle will be 60°. This is because the angle measurement starts from the positive x axis, and rotates 120° counter-clockwise. The angle formed at this point between the line and the x-axis (negative direction) is 60°.
The special right triangle formed will have a hypotenuse of 1, and a reference angle of 60°.
We know that the adjacent line, the line opposite the 30° angle, will be 1/2 the hypotenuse, or -1/2. Negative because it goes in the negative x direction.
The opposite end, or vertical side, will be √3/2.
sin(120) = opposite/hypotenuse = √3/2 ÷ 1 = √3/2
cos (120) = adjacent/hypotenuse = (-1/2) / 1 = -1/2
tan (120) = opposite / adjacent = (√3/2) / (-1/2) = -√3
1. Given
5.angle add post
6.substitution
Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is
Since there are n logs in the pile, so we get
Thus, the total number of logs in the pile is 6.
