Answer:
(49p2–490p) ÷(p–10)
Step-by-step explanation:
Answer: 3
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. Find the prime factorization of 27:
or 
2. The index of the radical is 3, therefore, you have rewrite it as following:
![\sqrt[3]{27}=\sqrt[3]{3^{3}}=3^{\frac{3}{3}}=3^{1}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%5Csqrt%5B3%5D%7B3%5E%7B3%7D%7D%3D3%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3D3%5E%7B1%7D%3D3)
3. Therefore, as you can see, the answer is 3.
So this would be a cubic graph because the largest exponent is a 3.
The Y-intercepts can be found by making all the x's equal 0, so then that would end up being -96 (makes sense considering a cubic graph intercepts at the origin, and this graph moves it down 96 units.
The X-intercepts (the zeros) are a bit tricky. We know that there will likely be three zeros because the exponent is a three. The zeros for this graph are 3, 4, and 8
So in Summary:
This is a Cubic graph with X-intercepts at (3,0), (4,0) and (8,0) and with Y-intercept at (0,-96)
Answer:
-15X^3y^2Z^2 is the answer
