<span>As the age of the U-235 sample is 2.631 billion years, and the half-life of U-235 is 713 million years, the sample has undergone 2.361 X 1,000,000,000 / 713 X 1,000,000 = 3.69 half lives. In each half-life the sample reduces to half its original weight according to the radioactive Half-Life Formula:
ln (Nt /N0) = -kt, where N0 = mass of the original weight of radioactive material, Nt = mass of radioactive material at time t, k = decay constant and t = time interval . We have to put Nt/N0 = 1/2 for time interval = half-life.</span>
Step-by-step explanation:
There are 40 DuBois students going on a field trip.
Each one pays their teacher $8.75 to cover admission to the museum and lunch.
Admission for the students is $120 and each one gets an equal amount to spend on lunch.
To Find :
How much will each DuBois student be able to spend on lunch.
Solution :
Amount they paid for admission :
\begin{gathered}P =\$ \dfrac{120}{40}\\\\P=\$3\end{gathered}P=$40120P=$3
Now, amount of money to spend on lunch is 8.75 -8.75−3 = $5.75 .
Hence, this is the required solution.
<span>At least one bear was sighted on 28 separate days in 40 day period total = 28/40
We're looking for the daily frequency of bear sightings, that's in the whole 40 day period.
Let's say 40 days period = 100%.
Then what's 28 days?
</span>
So the solution we're looking for would be (<span><span>28 days∗100) / </span>40 days = 70%</span>
The final answer is B. 70%.
<span>
</span>
Answer:
mnp = 30
<h3>Explanation:</h3>
Given: m= -2, n= 3, and p= -5
mnp = (-2)(3)(-5)
=> (-6)(-5)
=> 30
Start with y=mx+b
B is your y intercept
m is your slope
The points you have are (-1,4) and (1,-2)
To find the slow you Do Y2-Y1/X2-X1
(-2-4)/ (-1-1)
-6/-2
your m is 3
Now you go back to the equation of a Line y=mx+b
to find b (your y intercept) take on of the two points, and substitute it's y value in the equation Let's take (1,-2)
Y=mx+b
-2=3(1)+b
-2=3+b
b=-5
you now know that
b=-5
m=3x
The equation is
y=3x-5
