The volume of a cube is 64 cubic inches. what is the length of one side?
1 answer:
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Answer:
min at (3, 0 )
Step-by-step explanation:
given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= -
y = (x - 3)² = x² - 6x + 9 ← in standard form
with a = 1 and b = - 6 , then
= -
= 3
substitute x = 3 into the equation for corresponding value of y
y = (3 - 3)² = 0² = 0
vertex = (3, 0 )
• if a > 0 then vertex is minimum
• if a < 0 then vertex is maximum
here a = 1 > 0 then (3, 0 ) is a minimum
Answer:
Vertices at (-7, 5) and (-1, 5).
Foci at (-9, 5) and (1,5).
Step-by-step explanation:
(x + 4)²/9 - (y - 5)²/16 = 1
The standard form for the equation of a hyperbola with centre (h, k) is
(x - h²)/a² - (y - k)²/b² = 1
Your hyperbola opens left/right, because it is of the form x - y.
Comparing terms, we find that
h = -4, k = 5, a = 3, y = 4
In the general equation, the coordinates of the vertices are at (h ± a, k).
Thus, the vertices of your parabola are at (-7, 5) and (-1, 5).
The foci are at a distance c from the centre, with coordinates (h ± c, k), where c² = a² + b².
c² = 9 + 16 = 25, so c = 5.
The coordinates of the foci are (-9, 5) and (1, 5).
The Figure below shows the graph of the hyperbola with its vertices and foci.
