Answer:
Step-by-step explanation:
y=x²+7
vertex(0,7)
the length of latus rectum in a parabola equal to four times the focal length :
y=x²+7
focus X=-b/2a=0
focus Y=c- (b²-1)/4a=7+1/4=29/4
focus (0 , 29/4)
latus rectum is 29/4
(x-h)^2 = 4p (y-k) 4p is the length of the latus rectum with vertex(0,7)
(0-0)²=4p(29/4-7)
0=29p-28p=1p
the length of the latus rectum is 1
Answer:
second option
Step-by-step explanation:
Given
+ 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± 
= ± i ( noting that = i ), and
x² = - 5 ( take the square root of both sides )
x = ± 
= ± 
= ± 
× = ± i
Solutions are x = ± i and x = ± i
Use the (-b + - sqrt( b^2 - 4ac) ) /2a Formula.
a = 1 b= 10 c= 24
so you get .. (x+6 )(x+4) A
Answer:
-2/7
Step-by-step explanation:
2x+7y=14
7y=-2x+14
divide by 7
y=-2/7 x+2
Answer:
Step-by-step explanation:
3x < 4 - 1 or x > 31/9
3x < 3 or x > 31/9
x < 1 or x > 31/9
