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3 years ago

AB, CD, and EF are straight lines intersecting at point O. Find x.

Mathematics

1 answer:

frutty [35]3 years ago

8 0

Answer:

Firstly, identify all the pairs of vertically opposite angles. Vertically opposite angles are equal.

In this case,

AOC & DOB are vertically opposite angles so both of them are 2x°

EOD & COF are vertically opposite angles so they are both 3x°.

FOB & EOA are vertically opposite angles so they are both x°.

Adding the values of all 6 angles, we get:

3x + 3x + 2x + 2x + x + x = 12x

We also know that

12x = 360°

x = 30°

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For a rollerblading party there are 50 tickets available. Jason buys 6 tickets and Heather buys three times as many as Jason bou

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There should be 26 tickets left.

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3 years ago

Read 2 more answers

Find the value of x. A) 55 B) 60 C) 70 D) 125

Anna11 [10]

Answer:

x = 70°

Step-by-step explanation:

The given triangle has 2 equal sides and is therefore isosceles.

The base angles are equal, both 55°

To find x subtract the sum of the 2 angles from 180

x = 180° - (55 + 55)° = 180° - 110° = 70°

6 0

3 years ago

If f(x) = 3x - 5 and g(x) = x^2 - x what is the value of f(2/3)

9966 [12]

Answer:

x=5/3 hope i helped you

Step-by-step explanation:

7 0

3 years ago

What is the value of x? 20 35 60 70

baherus [9]

Answer:

20°

Step-by-step explanation:

Step 1:

x + 40° = 3x Vertical ∠'s

Step 2:

40° = 2x Subtract x on both sides

Step 3:

x = 40° ÷ 2 Divide

Answer:

x = 20°

Hope This Helps :)

8 0

3 years ago

On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number

Alina [70]

<h3>Question:</h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3>Answer:</h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3>Solution:</h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

Given items were sold for $356

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

$c \times 8 + p \times 10 = 356$

8c + 10p = 356 ----- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

p = 40 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

Substitute c = 22 in eqn 3

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0

4 years ago