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Thepotemich [5.8K]
3 years ago
14

Compute $\sqrt{25^2-7^2}$.

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

24

Step-by-step explanation:

\sqrt{25^2-7^2}\\\\=\sqrt{(25-7)(25+7)}\\\\=\sqrt{18(32)}\\\\=\sqrt{9*2*2^5}\\\\=\sqrt{3^2\cdot 2^6}\\\\=\sqrt{(3\cdot2^3)^2}\\\\=3\cdot2^3\\\\=3\cdot8\\\\=24

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Answer:

Null Hypothesis, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute

Alternate Hypothesis, H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute

Step-by-step explanation:

The null hypothesis is basically the problem statement i.e

Pulse rates of men have a standard deviation equal to 10 beats per minute

Hence, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute

The alternate hypothesis will contradict or negate the null hypothesis i.e

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Since we have given that

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