Answer:
Note that orthogonal to the plane means perpendicular to the plane.
Step-by-step explanation:
-1x+3y-3z=1 can also be written as -1x+3y-3z=0
The direction vector of the plane -1x+3y-3z-1=0 is (-1,3,-3).
Let us find a point on this line for which the vector from this point to (0,0,5) is perpendicular to the given line. The point is x-0,y-0 and z-0 respectively
Therefore, the vector equation is given as:
-1(x-0) + 3(y-0) + -3(z-5) = 0
-x + 3y + (-3z+15) = 0
-x + 3y -3z + 15 = 0
Multiply through by - to get a positive x coordinate to give
x - 3y + 3z - 15 = 0
Answer:
i don' think you can
Step-by-step explanation:
Answer: The variables have a weak positive correlation
Since r > 0, the correlation is positive. It's a weak correlation because r is closer to 0 than it is to 1.
<span>LJK = KJM
-10x +3 = -x + 21
-10x + x = 21 - 3
-9x = 18
x = -2
KJM = -x + 21 = 2 + 21 = 23
LJM = LJK + KJM
LJM = 23 + 23
LJM = 46º..
i think thats how its done </span>