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2 years ago

-(2-3t) what is this?

1 answer:

6 0

Answer:3t^2)^2. (3t2)2 ( 3 t 2 ) 2. Apply the product rule to 3t2 3 t 2 . 32(t2)2 3 2 ( t 2 ) 2. Raise 3 3 to the power of 2 2 . 9(t2)2 9 ( t 2 ) 2. Multiply the exponents in ...

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Step-by-step explanation:

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etty sets up a lemonade stand and charges $1 per glass. It cost her $50 to set up the stand. Which function gives the profit, p,

gizmo_the_mogwai [7]

If you would like to find the function that gives the profit Betty makes by selling a number of glasses of lemonade, you can find this using the following steps:
p ... profitg ... glasses of lemonade
f(g) = p = g * $1 - $50
The correct result would be f(g) = g * $1 - $50.
credit to Neuron, Ambitious
verified answer from him
brainly.com/question/1638432

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3 years ago

This ten frame shows 5+8. Draw to make 10. Then write the new fact.

o-na [289]

10=5+8=13-3 hope it helps!

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2 years ago

PLEASE help due today Geometry

irina1246 [14]

$\\ \sf\Rrightarrow \dfrac{15}{20}=\dfrac{21}{28}$

$\\ \sf\Rrightarrow \dfrac{1}{4}=\dfrac{1}{4}$

Hence they are similar

<A=<H
And ratio of sides are same

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$\\ \sf\Rrightarrow ∆KDH\sim ∆ABD$

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1 year ago

Why do you need to calculate mean, or modo of a set of data?

goldfiish [28.3K]

To find the average of the data

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2 years ago

A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion z-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

H₀: The proportion of women is same as men who exercise regularly, i.e. $p_{X}-p_{Y}=0$ .

Hₐ: The proportion of women is more than men who exercise regularly, i.e. $p_{X}-p_{Y}$ .

6 0

3 years ago

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