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2 years ago

Envision geometry 2018 question 1.3.9 answer

Mathematics

1 answer:

kozerog [31]2 years ago

8 0

Answer:

Jajajja

Step-by-step explanation:

Nejsjs

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Please help !!!!!!!!!!!!!!!!!!! what is A

algol13

Answer:

Step-by-step explanation:

a=11/12

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2 years ago

What is the first step in evaluating the expression below?

Ostrovityanka [42]

Answer:

brackets, then Parenthesis then the FIRST Multiplication then the division and then math and sub and so on a so for

Step-by-step explanation:

6 0

2 years ago

Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow

jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

$\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}$

Step-by-step explanation:

selecting the first team from n people we have $\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n$ possibility and choosing second team from the rest of n-1 people we have $\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1$

As { A, B} = {B , A}

Therefore, the total possibility is $\frac{n(n-1)}{2}$

Since our choices are allowed to overlap, the second team is $\frac{n(n-1)}{2}$

Possibility of choosing both teams will be

$\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}$

We now have the formula

1³ + 2³ + ........... + n³ = $[\frac{n(n+1)}{2}] ^{2}$

1³ + 2³ + ............ + (n-1)³ = $[x^{2} \frac{n(n-1)}{2}] ^{2}$

= $\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}$

4 0

3 years ago

Find the value of x. 2x 120° 700 A. 55 B. 35 C. 25 D. 10

monitta

Answer:

for this question you need to take the 12p and 700 and add then dived by 2x which then gives you your answer

7 0

2 years ago

Read 2 more answers

Look at the rectangle and the square:

OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = $\sqrt{180}$ ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = $\sqrt{72}$ ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

5 0

2 years ago

Read 2 more answers