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umka21 [38]
4 years ago
6

COULD SOMEONE HELP EXPLAIN THIS TO ME? I'M REALLY CONFUSED

Mathematics
1 answer:
ra1l [238]4 years ago
8 0

Answer:

B. 3.4 pizzas.

Step-by-step explanation:

We have been given a scatter plot, which represents the number of pizzas (y) sold during weeks when different numbers of coupons (x) were issued. The equation represents the linear model for this data: y=3.4x+43

We can see that our given equation is in form of slope intercept form: y=mx+b, where m= slope of line and b = y-intercept.

We can see from our given equation that y-intercept is 43, when no coupons were issued, there were 43 pizzas sold. 43 is constant and it will not change by any change in x.  

The slope of our line is 3.4, which represents change in number of pizzas with respect to change in number of coupons issued. Therefore, 3.4 more pizzas are sold for additional coupon issued and option B is the correct choice.

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The Midpoints of the line segment is (2, 5/2)

Step-by-step explanation:

The line is defined by starting and ending coordinates.

As given in the question starting coordinates are given as (3,-2) and the ending coordinates are provided as (1,7)

The midpoint of the life segment-

The midpoint of the line can be found by individually finding of each “x” and “y” coordinate from both ends.

Thus, x coordinate of the midpoint is (3+1)/2= 2

Similarly, the Y coordinate of the midpoint is (-2+7)/2 = 5/2

Hence the Midpoint of the life segment- (2, 5/2)

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Which expression is equivalent to 3(5 + 4)? (1 point)
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Step-by-step explanation:

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3 years ago
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Yuri thinks that 3/4 is a root of the following function.
sineoko [7]

Given:

The polynomial function is

q(x)=6x^3+19x^2-15x-28

Yuri thinks that \dfrac{3}{4} is a root of the given function.

To find:

Why \dfrac{3}{4} cannot be a root?

Solution:

We have,

q(x)=6x^3+19x^2-15x-28

If \dfrac{3}{4} is a root, then the value of the function at \dfrac{3}{4} is 0.

Putting x=\dfrac{3}{4} in the given function, we get

q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28

q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28

q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28

q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28

Taking LCM, we get

q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}

q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0

Since the value of the function at \dfrac{3}{4} is not equal to 0, therefore, \dfrac{3}{4} is not a root of the given function.

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3 years ago
at 1pm the level of water in the pool was 8 feet at 4pm the level of water was 2 feet find the constant rate of change of the wa
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Answer:

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Step-by-step explanation:

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<em>     3pm = 4ft </em>

4pm = 2ft

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