212°F
147°F
23.2 min
1) Initial temperature for t=0
T(0)=68+144e^(0)=68+144=212°F
2) After 15 min
T(15)=68+144e^(-0.04*15)=68+144e^(-0.6)=147°F
3) 125°F -> t=?
125=68+144e^(-0.04t)
144e^(-0.04t)=125-68=57
e^(-0.04t)=57/144=0.4 you can apply ln on both sides:
-0.04t=ln(0.4) solving you get t=23.3 min
Answer:D:Point A and point B are the same distance from the origin.
Step-by-step explanation:hope this helps
The slope of the line is calculated using
y2 - y1 / x2 - x1
Substituting the given values
-8 - 27 / 5 - 0 = -7
The rate of change or the slope is -7
And the initial value is the value of y when x is 0. From the first coordinates, the initial value is 27.
Answer:
-3 square root of 8 8/3 square root of 9
Answer:
NO
Step-by-step explanation:
Simply enter 5, 10 in the x and y boxes to get the answer.
10=6(5)-18
10=30-18
10=12
As a consequence, it isn't a feasible option.
