Question

The floor plan of a room has a scale of 2.5 in. : 35 ft. In the drawing, the length of the room is 8 in. and the width of the room is 6 in. What is the perimeter of the actual room?

Answer 1

Answer:

392 ft

Step-by-step explanation:

Hello, Let me help you with this

to find the real length and width you can use a rule of three

Step 1

length=8 in

Let

if

2.5 in ⇔ 35 ft

8 in ⇔ X ft ?

the relation is

$\frac{2.5\ in}{35\ feet}=\frac{8\ in }{x}\\\\solve\ for\ x\\\frac{x*2.5\ in}{35\ feet}=8\ in\\x*2.5\ in=8\ in *35\ feet\\x=\frac{8\ in *35\ feet}{2.5\ in}\\ x=112\ ft$  

Step 2

width=6 in

Let

if

2.5 in ⇔ 35 ft

6 in ⇔ X ft ?

the relation is

$\frac{2.5\ in}{35\ feet}=\frac{6\ in }{x}\\\\solve\ for\ x\\\frac{x*2.5\ in}{35\ feet}=6\ in\\x*2.5\ in=6\ in *35\ feet\\x=\frac{6\ in *35\ feet}{2.5\ in}\\ x=84\ ft$  

Step 2

find the perimeter using

Perimeter = 2*length +2* width

replacing

Perimeter= 2*112 ft +2* 84 ft

Perimeter=224 ft +168 ft

Perimeter=392 ft

Have a nice day

Answer 2

Well if I did my math correctly I do believe the perimeter should be 392 ft.


6÷2.5= 2.4
2.4×35=84

8÷2.5= 3.2
3.2×35=112

84×2
112×2
_____
392

you mult. by 2 because it's a room which usually has four walls and I imagined it being a rectangle.