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Hitman42 [59]
3 years ago
9

What is the HCF of 20 36 and 45??

Mathematics
2 answers:
tangare [24]3 years ago
6 0

20=1×2×2×5=1×4×5

36=1×2×2×9=1×4×9

45=1×3×3×5=1×9×5[/tex]

  • HCF=1
PIT_PIT [208]3 years ago
6 0

Answer:

1

Step-by-step explanation:

Common Factor of

20 = 2×2×5×1

36 = 2×2×3×3×1

45 = 3×3×5×1

By the following factors 1 is common

Therefore, HCF of 20 36 and 45 is 1

Hope it helps !

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nataly862011 [7]

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Rewrite 75 as 5^2 * 3

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Pull squared terms out from the radical to get 5√3

3 0
3 years ago
Stan’s Car Rental charges $35 per day plus $0.25 per mile. Denise wants to rent one of Stan’s cars, keeping the total cost of th
Greeley [361]
$55-$35=20
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What’s the answerrr..........
Afina-wow [57]

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8 0
2 years ago
Is y=3x+4 parallel or perpendicular
Sauron [17]

Answer: y=3x+4 is parallel to y=3x+7

Step-by-step explanation:

<h3> The complete exercise is: "Is y=3x+4 parallel, perpendicular or neither to y=3x+7?"</h3><h3 />

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

First, in order to solve this exercise it is important to remember that, by definition:

1. The slopes of parallel lines are equal.

2. The slopes of perpendicular lines are negative reciprocal.

In this case, you have the following line given in the exercise:

 y=3x+4

You can identify that "m" and "b" are:

m=3\\b=4

And the other line provided in the exercise is this one:

y=3x+7

So, you can identify that:

m=3\\b=7

As you can notice, the slopes of both lines are equal; therefore, you can conclude that those lines are parallel.

6 0
3 years ago
A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.
REY [17]

The question is incomplete as the cost price isn't given. However, taking the cost price as x :

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.

Let :

Cost price when new = x

Cost price when sold = 4/5 * cost price when new

Cost when sold = 4/5 of x = 4x/5

Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)

Hence,

Amount of money lost on the car = (x - 4x/5)

x - 4x/5 = (5x - 4x) / 5 = x / 5

To obtain the exact price, kindly input the omitted cost when new for x.

7 0
2 years ago
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