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Mrac [35]
3 years ago
8

A political candidate wanted to understand what issues were important to their voters. They asked 1,999 voters, "Which issue is

the most important: crime, city planning, or health care?" The results of the survey are shown in the two-way table below in the attachment:
What is the probability that a person chosen at random from this survey is concerned about crime, given that they are male? Round your answer to the nearest tenth.

A. 5.9%
B. 14.5%
C. 22.0%
D. 26.8%

Mathematics
2 answers:
marusya05 [52]3 years ago
7 0

This one is just some simple division, an example in the lesson is this question exact but with different numerical values. It is 14.5%, which doesn't make much sense with the context.

The answer is B, 14.5%! Feel free to ask further questions about this topic!

Alla [95]3 years ago
6 0

Answer: B. 14.5%

Step-by-step explanation:

Let M be the event of choosing a person that is male and c be the event of choosing a male who is concerned about crime.

From the given table , The number of males concerned about crime = 118

The probability of choosing a person that is male =P(C\capM)=\frac{118}{1999}

The number of males surveyed = 118+239+458=815

P(M)=\frac{815}{1999}

Now,  the probability that a person chosen at random from this survey is concerned about crime, given that they are male is given by:-

P(C|M)=\frac{P(C\capM)}{P(M)}\\\\=\frac{\frac{118}{1999}}{\frac{815}{1999}}\\\\=\frac{118}{815}=0.145\\=0.145\times100\%=14.5%

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Step-by-step explanation:

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square root of 58 is about 8.

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0, 2, 8, 10
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3 years ago
10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.
erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

p = \frac{4}{6} = 0.6667

10 normal six sided dice are thrown.

This means that n = 10

Find the probability of obtaining at least 8 failures.

This is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951

P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867

P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174

Then

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992

0.2992 = 29.92% probability of obtaining at least 8 failures.

8 0
3 years ago
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