Answer:
Explanation:
I will show my thinking using words and numbers.
The fact that when the camels walked in rows of 2 one walked alone means tha the number of camels divided by 2 leaves a remainder of 1. Also, that means that if you subtract 1 from the number of camels, the new number is a multiple of 2. This is:
- The number of camels less 1 is a multiple of 2.
With the same reasoning, you obtain:
- The number of camels less 1 is a multiple of 3.
- The number of camels less 1 is a multiple of 4.
- The number of camels less 1 is a multiple of 5.
Now, the numbers of camels less 1 is a multiple of 2, 3, 4, and 5. Now, let's search the first (least) common multiple of 2, 3, 4, and 5.
For that, you have to factor each number into its prime factors:
The least common multiple is the product of the common and uncommon factors, each raised to its highest power: 2² × 3 × 5 = 60.
Remember that 60 is the number of camels less 1, thus the number of camels is 60 + 1 = 61.
The next common multiple is 2 × 60 = 120, which exceeds 100 thus the only possible value is the one determined above.
Now you can prove that 61 meets the conditions:
- 61 ÷ 2 = 30, plus one (remainder): means that 60 camels walked in 30 rows of 2 and one walked alone.
- 61 ÷ 3 = 20, plus one: 60 camels walked in 20 rows of 3 and one walked alone.
- 61 ÷ 4 = 15, plus one: 60 camels walked in 14 rows of 4 and one walked alone.
- 61 ÷ 5 = 12, plus one: 60 camels walked in 12 rows of 5 and one walked alone.
Answer:
B) (-3, 5) and (1, 5)
Step-by-step explanation:
Answer:
subtract the x from the other x and the y from the other y. Put that equation in a square root.
If you factor 4x²-12x, you can divide 4x from each term.
4x² ÷ 4x = x
-12x ÷ 4x = -3
Therefore, the other term becomes (x-3) because 4x(x-3) = 4x²-12x
