Answer:
5/6 (i think im not good at math soz)
-Mina
Step-by-step explanation:
Branily stop deleting my awnsers
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
7 day in a week so 3/5×7= 4.2
or 4 1/5 bales of hay
When dividing 1/8 by 2
we have to first take the reciprocal of 2
reciprocal is when the numerator and denominator are exchanged
2 when written as a fraction is

we need to find the reciprocal of

which is

then

when 'of' function is used it means to multiply the 2 fractions
when multiplying fractions multiply the numerators by numerators and multiply denominators by denominators
is

answer is