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Ivanshal [37]
3 years ago
15

Can someone please help me with this question!!!!!

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0
I think it's C biceptor
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Using the Slope-intercept form, the slope is - 2.

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Factor each expression 36abc +54ad
olya-2409 [2.1K]

Answer:

18a(2bc + 3d)

Step-by-step explanation:

36abc + 54ad

Step 1: Find the Highest Common Factor of each

36abc = 2×2×3×3×a×b×c = 18a × 2bc

54ad = 2×3×3×3×a×d = 18a × 3d

HCF = 2×3×3×a = 18a

Step 2: Factor out with HCF

18a(2bc + 3d)

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3 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
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